(5x+2)(3x^2-20x-7)=0

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Solution for (5x+2)(3x^2-20x-7)=0 equation:


Simplifying
(5x + 2)(3x2 + -20x + -7) = 0

Reorder the terms:
(2 + 5x)(3x2 + -20x + -7) = 0

Reorder the terms:
(2 + 5x)(-7 + -20x + 3x2) = 0

Multiply (2 + 5x) * (-7 + -20x + 3x2)
(2(-7 + -20x + 3x2) + 5x * (-7 + -20x + 3x2)) = 0
((-7 * 2 + -20x * 2 + 3x2 * 2) + 5x * (-7 + -20x + 3x2)) = 0
((-14 + -40x + 6x2) + 5x * (-7 + -20x + 3x2)) = 0
(-14 + -40x + 6x2 + (-7 * 5x + -20x * 5x + 3x2 * 5x)) = 0
(-14 + -40x + 6x2 + (-35x + -100x2 + 15x3)) = 0

Reorder the terms:
(-14 + -40x + -35x + 6x2 + -100x2 + 15x3) = 0

Combine like terms: -40x + -35x = -75x
(-14 + -75x + 6x2 + -100x2 + 15x3) = 0

Combine like terms: 6x2 + -100x2 = -94x2
(-14 + -75x + -94x2 + 15x3) = 0

Solving
-14 + -75x + -94x2 + 15x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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